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38 Pages·2011·0.57 MB·English

TS – X– MJ – XII-VI

TTAARRGGEETT -- AAIIPPMMTT

(MEDICAL ENTRANCE EXAMINATION)

(Class XII / XII pass student)
MAJOR TEST # 6 (PRE PATTERN)

PHYSICS, CHEMISTRY, BIOLOGY
Syllabus :
Physics : Full Syllabus
Chemistry : Full Syllabus
Biology : Full Syllabus

Duration : 3 Hrs. Max. Marks : 800

Name :________________________________________________________ Roll No. : ________________________

Instructions to Candidates L
A
GENERAL:
E
S
1. This paper contains 200 Qs. in all. All questions are compulsory.

2. There is Negative Marking. Guessing of answer is harmful.

3. Write your Name & Roll No. in the space provided on this cover page of question paper.
4. The question paper contains blank space for your rough work. No additional sheet will be
provided for rough work.
5. The answer sheet, machine readable Optical Mark Recognition (OMR) is provided separately.
6. Do not break the seals of the question paper booklet before being instructed to do so by the
invigilator.

7. Blank papers, Clipboards, Log tables, Slide Rule, Calculators, Cellular Phones, Pagers and

Electronic Gadgets in any form are not allowed to be carried inside the examination hall.

MARKING SCHEME:

1. Each Question has four options, only one option is correct. For each incorrect response, one-mark

would be deducted.

2. In Physics : Q. 1 - 50 carry 4 marks each,

In Chemistry : Q. 51 - 100 carry 4 marks each,

In Biology : Q. 101 - 200 carry 4 marks each,

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Ph: 0744-3040000 (6 lines), Fax [phone]
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Now, Schedule practice questions are available on internet also, Visit www.examtayari.com
Space for Rough Work (jQ dk;Z gsrq LFkku)

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PHYSI CS

iz'u ls rd cgqfodYih iz'u gSaA izR;sd iz'u ds pkj
Q uestions 1 to 45 are multiple choice questions. Each 1 45
qu estion has four choices (1), (2), (3) and (4), out of fodYi (1), (2), (3) rFkk (4) gSa, ftuesa ls dsoy ,d fodYi
w hich ONLY ONE is correct. lgh gSA

fuEu ;qXeksa esa ls fdldh foek;sa ,d leku ugha gS
Q.1 -
Q.1 Out of the following pair, which one does NOT

dk;Z rFkk cyk?kw.kZ
have identical dimensions is- (1)
(1) work and torque (2) tM+Ro vk?kw.kZ rFkk cy vk?kw.kZ
(2) moment of inertia and moment of a force vkosx rFkk laosx
(3)
(3) impulse and momentum
dks.kh; laosx rFkk Iykad fu;rkad
(4) angular momentum and Plank's constant (4)

,d vkur ry {kSfrt ds lkFk dks.k cukrk gSA ry
Q.2 An inclined plane makes an angle θ with the Q.2 θ

horizontal. A groove cut in the plane makes an esa OX ds lkFk α dk.s k cukr s g;q s ,d [kkapk (groove)
angle α with OX. The acceleration of a body which dkVk tkrk gSA xq:Ro ds izHkko esa [kkaps esa ls Lora=k
is free to slide down the groove under the influence
:i l s uhps fQlyu s okyh ,d oLr q dk Roj.k g S
-
of gravity is-

θ
θ α
α X
X O
O
(1) g (2) g sin θ (1) g (2) g sin θ
(3) g sin θ cos α (4) g sin θ sin α (3) g sin θ cos α (4) g sin θ sin α

Q .3 Refer to figure. All surfaces are frictionless. The Q.3 fp=k esa] lHkh lrgsa ?k"kZ.k jfgr gSA T1 rFkk T2 dk
vuqikr gS
ratio of T and T is- -
1 2
F
F T T
T T 2 1
3kg 2 12kg 1 15kg 30° 3kg 12kg 15kg 30°

(1) 1 : 5 (2) 5 : 1 (3) 4 : 1 (4) 1 : 4
(1) 1 : 5 (2) 5 : 1 (3) 4 : 1 (4) 1 : 4

,d oLrq ij ,d cy }kjk dk;Z fd;s tkus ij
Q .4 A body acted upon by a force F has an acceleration Q.4 F
'A'. When it is acted upon by two forces each of Roj.k gSA tc bl ij ifjek.k okys nks cy
'A' F

magnitude F at right angles to each other, its
ijLij yEcor~ dk;Z djrs gS] rks bldk Roj.k gksxk
-
acceleration will be -

(1) 2A (2) A (3) A 2 (4) 2 (1) 2A (2) A (3) A 2 (4) 2

,d CykWd dks >qdko dks.k ds vkur ry ij osx
Q.5 A block is projected up an inclined plane of Q.5 30° v

inclination 30° with velocity v. If µ is the ds lkFk Åij iz{kfsir fd;k tkrk gSA ;fn µ ?k"kZ.k xq.kkda
coefficient of friction, then the block moves up a gks] rc CykWd Åij dh vksj fuEu nwjh r; djrk gS
-
distance of-
v2 v2
v2 v2 (1) (2)
(1) (2) g(1+ 3µ) g
g(1+ 3µ) g
v2 v2
v2 v2 (3) (4)
(3) (4) 1+ 3µ µ
1+ 3µ µ

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Q .6 An electric motor of 100 W power drives a stirrer Q .6 100 W 'kfDr dh ,d fo|qr eksVj ikuh ds ,d Vc esa

in a water bath. Only 80% of the energy supplied to ,d foyksMd dks pykrh gSA eksVj dks lIykbZ dh xbZ

the motor is used up in stirring water. The work ÅtkZ dk dsoy 80% Hkkx gh ikuh dks foyksfMr djus esa
done on water in 1 second is- dke vkrk gSA lsd.M esa ikuh ij fd;k x;k dk;Z gS
1 -
(1) 100 J (2) 80 J (3) 180 J (4) 145 J
(1) 100 J (2) 80 J (3) 180 J (4) 145 J

;fn ,d ?kw.khZ IysVQkeZ dh vko``fÙk rFkk ,d yM+ds
Q.7 If the frequency of the rotating platform is f and the Q.7 f

distance of a boy from the centre is r, what is the dh dsUnz ls nwjh r gks] rks yM+ds dks dsUnz ls feykus
area swept out per second by the line connecting okyh js[kk }kjk izfrlsd.M fdruk {ks=kQy
?
the boy to the centre ?
(1) πrf (2) 2πrf (3) πr2f (4) 2πr2f (1) πrf (2) 2πrf (3) πr2f (4) 2πr2f

,d ?kw.kZu dj jgh ?kw.khZ Vscy ij j[kk ,d flDdk Bhd
Q.8 A coin placed on a rotating turntable just lips if it Q.8

fQly tkrk gS ;fn bl s dsUnz ls dh nwjh ij j[kk
is placed at a distance of 4 cm from the centre. If 4 cm
the angular velocity of the turntable is doubled, it tkrk gSA ;fn ?kw.khZ Vscy dk dks.kh; osx nqxquk gks tk;s]
will just slip at a distance of- rks ;g fdl nwjh ij Bhd fQly tkrk g S-

(1) 1cm (2) 2 cm (3) 4 cm (4) 8 cm (1) 1cm (2) 2 cm (3) 4 cm (4) 8 cm

,d d.k ,d Å/okZ/kj o`Ùk ds 'kh"kZre fcUnq ls
Q.9 A particle crosses the top most point H of a vertical Q.9 H

Økafrd pky ds lkFk xqtjrk gSA rc fcUnqvksa
circle with critical speed. Then the ratio of
o ij osxksa dk vuqikr gS
velocities at points L, M and H is- L, M H -
H H

90° M 90° M

90° 90°

L L
(1) 3 : 2 : 1 (2) 5 : 3 : 1 (1) 3 : 2 : 1 (2) 5 : 3 : 1
(3) 52 : 32 : 12 (4) 5: 3: 1 (3) 52 : 32 : 12 (4) 5: 3: 1

fn;k gS ,d vkd`fr dk ,d leku rkj ftldh
Q.10 Given : A U-shaped uniform wire of sides 2l, land Q.10 : U-

l. The x and y co-ordinates of the centre of mass of Hkqtk;sa 2l, l rFkk l gSA izR;sd Hkqtk esa nzO;eku dsUnz ds
each side are shown in figure. The x and y co- o funsZ'kkad fp=kkuqlkj gSA rkj ds nzO;eku dsUnz
x y

ordinates of the centre of mass of wire are
ds x o y funsZ'kkad Øe'k% gS -
respectively -

y y

2l,2l 2l,2l
2l (0, l) 2l (0, l)

l ,0 l ,0
2  2 
O l x O l x

l l   l  l 
(1) l , l  (2) (l, l) (3) l, l  (4) l ,l (1) 4, 4 (2) (l, l) (3) l, 4 (4) 4,l
4 4  4 4 

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Q . 11 In forced oscillation of a particle, the amplitude is Q .11 ,d d.k ds d`f=ke nksyu esa, cy dh vko`fÙk ω1 ds
maximum for a frequency ω1 of the force, while the fy, vk;ke vf/kdre gksrk gS tcfd cy dh vko`fÙk
energy is maximum for a frequency ω of the
2 ω ds fy, ÅtkZ vf/kdre gksrh gS] rc -
force ; then - 2

(1) ω < ω when damping is small and ω > ω (1) ω < ω tc voeanu vYi gS rFkk ω > ω tc
1 2 1 2 1 2 1 2
when damping is large voeanu vf/kd gS

(2) ω > ω (2) ω > ω
1 2 1 2

(3) ω1 = ω2 (3) ω1 = ω2
(4) ω < ω
(4) ω < ω 1 2
1 2

yEckbZ rFkk nzO;eku dh ,d le:i psu ,d
Q.12 A uniform chain of length L and mass M overhangs Q.12 L M

{kSfrt est ls blizdkj yVdh gqbZ gS fd bldk nks
a horizontal table with its two-third part on the

frgkbZ Hkkx est ij gksrk gSA est rFkk psu ds e/;
table. The friction coefficient between the table and
the chain is µ. The work done by the friction during ?k"kZ.k xq.kkad µ gSA ml vof/k ds e/; ?k"kZ.k }kjk
fd;k x;k dk;Z tc psu est ls fQly tkrh gS
the period the chain slips off the table is- -

1 2 1 2
(1) − µMgL (2) − µMgL (1) − µMgL (2) − µMgL
4 9 4 9
4 6
(3) −4µMgL (4) −6µMgL (3) − µMgL (4) − µMgL
9 7
9 7

Q. 13 A geostationary satellite is orbiting the Earth at a Q.13 ,d HkwfLFkj mixzg i`Foh dh lrg ds Åij 6R Å¡pkbZ

height of 6R above the surface of the Earth, Rbeing ij i`Foh dk ifjØe.k dj jgk gSA R i`Foh dh f=kT;k

the radius of the Earth. The time period of another gSA i`Foh dh lrg ls Å¡pkbZ ij vU; mixzg
2.5R
satellite at a height of 2.5R from the surface of
dk vkorZdky gS
-
Earth is-

(1) 6 2h (2) 6h (3) 6 3h (4) 10 h (1) 6 2h (2) 6h (3) 6 3h (4) 10 h

Q. 14 The radius of the Earth shrinks by 1%, its mass Q.14 i`Foh dh f=kT;k 1% ladqfpr gks tkrh gS tcfd
remaining the same. The percentage change in the bldk nzO;eku leku cuk jgrk gS] rks g ds eku esa
value of g is- izfr'kr ifjorZu gS
-

(1) –2 % (2) + 2% (3) –3 % (4) + 4%
(1) –2 % (2) + 2% (3) –3 % (4) + 4%

Q. 15 A fast moving neutron suffers one-dimensional Q.15 ,d rhoz xfreku U;wVªkWu ,d ukfHkd N14 ds lkFk
7
elastic collision with a nucleus N14. What
7 ,dfoeh; izR;kLFk VDdj djrk gSA VDdj esa U;wVªkuW

approximate percentage of energy is lost by the
}kjk yxHkx fdrus izfr'kr ÅtkZ dh gkfu gksrh gS
neutron in the collision ? ?

(1) 5 % (2) 10 % (3) 25 % (4) 0 % (1) 5 % (2) 10 % (3) 25 % (4) 0 %

nkc o rki ij vkWDlhtu ds ds fy, voLFkk
Q.16 The equation of state for 5 g of oxygen at a Q.16 P T 5 g

lehdj.k tc vk;ru izkIr dj fy;k tkrk gS]
pressure P and temperature T, when occupying a V

volume V, will be- gksxh]
(1) PV = 5RT (2) PV = (5/2) RT (1) PV = 5RT (2) PV = (5/2) RT
(3) PV = (5/16) RT (4) PV = (5/32) RT (3) PV = (5/16) RT (4) PV = (5/32) RT
tgk¡ xSl fu;rkad gSA
R
Where R is the gas constant.

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Q .17 Which of the following circular rods (given radius r Q .17 fuEu o`Ùkkdkj NM+ksa (f=kT;k r o yEckbZ l) tks izR;sd

and length l) each made of the same material and leku inkFkZ ls cuh gS rFkk ftuds fljs leku rki

whose ends are maintained at the same temperature ij j[ks gSa] eas ls dkSulh lcls vf/kd Å"ek dk pkyu

will conduct most heat ? djsxh
?

(1) r = r0; l = l0 (2) r = 2r0; l = l0 (1) r = r0; l = l0 (2) r = 2r0; l = l0
(3) r = 2r ; l = 2l (4) r = r ; l = 2l (3) r = 2r ; l = 2l (4) r = r ; l = 2l
0 0 0 0 0 0 0 0

Q .18 During an adiabatic process, the pressure of a gas is Q.18 ,d :)ks"e izØe ds nkSjku ,d xSl dk nkc blds
found to be proportional to the cube of its absolute ije rki ds ?ku ds vuqØekuqikrh ik;k tkrk gSA xSl
temperature. The ratio Cp/Cv for the gas is- ds fy, Cp/Cv gS -
3 4
(1) (2) 3 4
2 3 (1) (2)
2 3

(3) 2 (4) 5 (3) 2 (4) 5
3 3

layXu xzkQ esa fofdj.k mRltZu ds dkj.k leku
Q .19 The graph, shown in the adjacent diagram, Q.19
represents the variation of temperature (T) of two i`"Bh; {ks=kQy okyh nks oLrqvksa x o y ds rki (T) dk
le; ds lkFk ifjorZu n'kkZ;k x;k gS] rks nksukas dh
bodies x and y having same surface area, with time (t)
oLrqvksa dh mRltZu {kerk rFkk vo'kks"k.k {kerk
(t) due to the emission of radiation. Find the correct (e)
ds e/; lgh lEcU/k Kkr djsaA
relation between the emissivity (e) and absorptivity (a)

power (a) of the two bodies.

y

x
y T

x
T t

(1) e > e ,oa a < a (2) e < e ,oa a > a
t x y x y x y x y
(3) e > e ,oa a > a (4) e < e ,oa a < a
(1) e > e and a < a (2) e < e and a > a x y x y x y x y
x y x y x y x y
(3) ex > ey and ax > ay (4) ex < ey and ax < ay

;fn lw;Z dk rki c<+dj ls rFkk bldh f=kT;k
Q.20 If the temperature of the sun were to increase from Q.20 T 2T

T to 2T and its radius from R to 2R, then the ratio of R ls 2R gks tk;s] rc i`Foh ij izkIr fofdj.k ÅtkZ dk
the radiant energy received on earth to what it was
blds iwoZ eku ds lkFk vuqikr gksxk
-
previously will be-

(1) 32 (2) 16 (1) 32 (2) 16
(3) 4 (4) 64 (3) 4 (4) 64

,d ek/;e esa ,d d.k dk foLFkkiu fuEu izdkj
Q .21 The displacement y of a particle in a medium can Q.21 y
be expressed as iznf'kZr fd;k tk ldrk gS

y = 10–6 sin (100t + 20x + π/4)m y = 10–6 sin (100t + 20x + π/4)m
where t is in second and x in metre. The speed of tgk ¡ lsd.M e as rFkk ehVj e as gSA rjxa dh pky gS
t x -
the wave is-
(1) 20 m/s (2) 5 m/s
(1) 20 m/s (2) 5 m/s

(3) 2000 m/s (4) 5π m/s
(3) 2000 m/s (4) 5π m/s

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Q . 22 A tuning fork of known frequency 256 Hzmakes 5 Q .22 vKkr vko`fÙk 256 Hz dk ,d Lofj=k f}Hkqt ,d
beats per second with the vibrating string of a fi;kuks dh dfEir Mksjh ds lkFk 5 foLiUn izfr lsd.M
piano. The beat frequency decreases to 2 beats per nsrk gSA foLiUn vko`fÙk ?kVdj 2 foLiUn izfr lsd.M
second when the tension in the piano string is gks tkrh gS] tc fi;kuks Mksjh esa ruko FkksM+k lk c<+

tkrk gSA fi;kuks Mksjh dh vko`fÙk ruko c<+us ds
slightly increased. The frequency of the piano
iwoZ Fkh
string before increasing the tension was- -
(1) (256 + 5) Hz (2) (256 + 2) Hz (1) (256 + 5) Hz (2) (256 + 2) Hz

(3) (256 – 2) Hz (4) (256 – 5) Hz
(3) (256 – 2) Hz (4) (256 – 5) Hz

Q. 23 An earthquake generates both transverse (S) and Q.23 ,d HkwdEi i`Foh esa vuqizLFk (S) rFkk vuqnS/;Z (P) nksuksa

izdkj dh /ofu rjaxs mRiUu djrk gSA rjaxksa dh pky
longitudinal (P) sound waves in the earth. The S
speed of S waves is about 4.5 km/s and that of P yxHkx 4.5 km/s rFkk P rjaxksas dh pky yxHkx

waves is about 8.0 km/s. A seismograph records P gSA ,d HkwdEi ys[kh HkwdEi ls izkIr
8.0 km/s
and S waves from an earthquake. The first P wave
P rFkk S rjaxksa dks fjdkWMZ djrk gSA izFke P rjax]
arrives 4.0 minute before the first S wave. The
izFke rjax ds feuV iwoZ igq¡prh gSA HkwdEi dk
epicentre of the earthquake is located at a distance S 4.0
dsUnz yxHkx fuEu nwjh ij fLFkr gksrk gS-
of about

(1) 25 km (2) 250 km (1) 25 km (2) 250 km
(3) 2500 km (4) 5000 km (3) 2500 km (4) 5000 km

Q. 24 A star is moving away from the Earth with a Q.24 ,d rkjk 105 ms–1 ds osx ls i`Foh ls nwj xfreku gSA
velocity of 105 ms–1. The shift in the spectral line of 5700 Å rjaxnS/;Z dh LisDVªeh js[kk esa foLFkkiu tks fd

wavelength 5700 Å, as observed on Earth, is- i`Foh ij izsf{kr fd;k tkrk gaS] gS
-
(1) 0.53 Å (2) 1.06 Å
(1) 0.53 Å (2) 1.06 Å
(3) 1.90 Å (4) 3.08 Å
(3) 1.90 Å (4) 3.08 Å

Q. 25 An engine running at speed v sounds a whistle of Q.25 ,d batu v pky ls nkSM+rk gqvk 600 Hz vko`fÙk dh
10 10

frequency 600 Hz. A passenger in a train coming ,d lhVh ctkrk gSA ,d Vsªu tks foijhr fn'kk ls
from the opposite side at speed v experiences v pky ls vk jgh gS] esa cSBs ,d ;k=kh dks lhVh dh
15 15

vko`fÙk vuqHko gksrh gSA ;fn ok;q esa /ofu dh pky
this whistle to be of frequency f. If v is speed of f
sound in air and there is no wind, f is nearest to. v gS rFkk ok;q izfrjks/k ugha gS] rks f yxHkx gS&

(1) 710 Hz (2) 630 Hz (1) 710 Hz (2) 630 Hz

(3) 580 Hz (4) 510 Hz (3) 580 Hz (4) 510 Hz

Q. 26 A charged oil drop is suspended in a uniform field Q.26 ,d vkosf'kr rsy cwan 3 × 104 V/m ds ,d le:i

of 3 × 104 V/m so that it neither falls nor rises. The fo|qr{ks=k esa fuyfEcr gS bl izdkj fd ;g u rks

charge on the drop will be- (Take the mass of the fxjrh vkSj u gh mBrh gSA cwan ij vkos'k gksxk –

charge = 9.9 × 10–15 kg and g = 10 m/s2) (vkos'k dk nzO;eku = 9.9 × 10–15 kg rFkk g = 10 m/s2)

(1) 1.6 × 10–18 C (2) 3.2 × 10–18 C (1) 1.6 × 10–18 C (2) 3.2 × 10–18 C

(3) 3.3 × 10–18 C (4) 4.8 × 10–18 C (3) 3.3 × 10–18 C (4) 4.8 × 10–18 C

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Q .27 In figure, a fuse in one of the bulbs causes all the fp=k esa] ,d cYc ds ¶;wt gksus ij ckfd lHkh cYc
Q.27

other to go out. Which bulb has fused ? cq> tkrs gSaA rks dkSulk cYc ¶;wt gksrk gS ?

1 2 3 1 2 3
4 5 4 5

(1) 1 (2) 2 (3) 3 (4) 4 or 5 (1) 1 (2) 2 (3) 3 (4) 4 or 5

Q.28 Four capacitors are connected as shown in figure. Q.28 pkj la/kkfj=k fp=kkuqlkj tqM+s gSaA 8µF /kkfjrk ds

The approximate charge and potential across 8µF la/kkfj=k ij vkos'k rFkk foHko ds eku gksasxs Øe'k% &
capacitance will be respectively

6µF 4µF 8µF 36µF
6µF 4µF 8µF 36µF
A B
A B
40 volt
40 volt oksYV oksYV
(1) 320 µC; 40 (2) 400µC; 50
(1) 320 µC; 40 volt (2) 400µC; 50 volt
oksYV oksYV
(3) 213µC; 27 (4) 360µC; 45
(3) 213µC; 27 volt (4) 360µC; 45 volt

Q.29 ¶;wt rkj og rkj gS ftldk-
Q.29 Fuse wire is a wire of -
mPp izfrjks/k rFkk mPp xyukad gS
(1) high resistance and high melting point (1)
mPp izfrjks/k rFkk vYi xyukad gS
(2) high resistance and low melting point (2)
vYi izfrjks/k rFkk vYi xyukad gS
(3) low resistance and low melting point (3)
vYiizfrjks/k rFkk mPp xyukad gS
(4) low resistance and high melting point (4)

Q.30 In the potentiometer circuit shown in figure. V and Q.30 fp=k esa iznf'kZr foHkoekih ifjiFk esa V rFkk R rkj MN ij

R are set to give a potential gradient 10 mV/cm on 10 mV/cm dh foHko izo.krk fn;s tkus ds fy, O;ofLFkr
the wire MN. If R' = 2.000 ohm, and the null point gSA ;fn R' = 2.000 vkse rFkk vfo{ksi fcUnq MP= 82.8 cm
occurs at MP = 82.8 cm, the current through R' is ij izkIr gksrk gS] rks R' ls izokfgr /kkjk gS&

V R V R

P P
M M
N N

R' G R' G

(1) 0.414 A (2) 0.828 A (1) 0.414 A (2) 0.828 A
(3) 1.656 A (4) 0.207 A (3) 1.656 A (4) 0.207 A

Q .31 A charged particle of energy 15 eV moves through Q.31 15 eV ÅtkZ dk ,d vkosf'kr d.k ,d yEcor~
pqEcdh; {ks=k ls xqtjrk gSA pqEcdh; {ks=k ls ckgj
a perpendicular magnetic field. The energy of the

fudyus ij d.k dh ÅtkZ gS
particle on emerging out of the magnetic field is- -
(1) 15 eV (1) 15 eV
(2) > 15 eV
(2) > 15 eV
(3) < 15 eV
(3) < 15 eV
ls vf/kd ;k de ;g vkjksfir {ks=k dh
(4) 15 eV
(4) may be more or less than 15 eV depending on
izd`fr ij fuHkZj djrk gS
the sense of the applied field

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Q .32 A frog can be levitated in a magnetic field produced Q .32 ,d esa<d ds uhps j[kh Å/okZ/kj ifjukfydk esa /kkjk esa

by a current in a vertical solenoid placed below the mRiUUk pqEcdh; {ks=k esa esa<d mNyk tkrk gSA ;g

frog. This is possible because the body of the frog blfy, laHko gS] D;ksafd esa<d dk 'kjhj O;ogkj djrk gS
-
behaves as-
(1) vuqpqEcdh; inkFkZ dh rjg
(1) paramagnetic izfr pqEcdh; inkFkZ dh rjg
(2)
(2) diamagnetic
ykSg pqEcdh; inkFkZ dh rjg
(3) ferromagnetic (3)
(4) antiferromagnetic (4) izfr ykSg pqEcdh; inkFkZ dh rjg

izR;korhZ /kkjk vehVj }kjk ugha ekih tk ldrh
Q.33 Alternating current can not be measured by DC Q.33 DC

ammeter because- gS D;kasfd -

(1) average value of current for complete cycle is zero. (1) lEiw.kZ pØ ds fy, /kkjk dk vkSlr eku 'kwU; gksrk g S
(2) AC changes direction (2) AC fn'kk ifjofrZr djrh gS
(3) AC can not pass through DC ammeter vehVj ls ugha xqtj ldrh
(3) AC , DC
(4) DC ammeter will get damaged
vehVj {kfrxzLr gks tkrk gS
(4) DC
,d /kkfRod NM+ xq:Ro ds vUnj bl izdkj fxjrh gS fd
Q.34 A metallic rod falls under gravity with ends Q.34
blds fljs iwoZ rFkk if'pe fn'kk eas funsZf'kr gksA rc
pointing in the direction east and west. Then- -

blesa ,d fo-ok-cy izsfjr gksrk gS tc blds
(1)
(1) an emf is induced in it as it cuts H (horizontal)
{kSfrt dkVk tkrk gS

(2) no emf is induced at all dksbZ fo- ok- cy izsfjr ugh gksrk
(2)
(3) two emf's of equal but opposite signs are nks cjkcj rFkk foijhr fpUgksa ds fo-ok- cy izsfjr
(3)
induced giving no net emf. gksrs gS tks dqy fo-ok-cy 'kwU; nsrs gSa
xq:Rokd"kZ.k {ks=k bldh uhps dh vksj xfr dk
(4) the gravitational field opposes its downward (4)
fojks/k djrk gS
motion

fuEu xksyh; ySalksa esa ls dkSulk fo{ksi.k ugha n'kkZrk gS
Q.35 Which one of the following spherical lenses does Q.35 ?

not exhibit dispersion ? The radii of curvature of ySalks dh i`"Bksa dh oØrk f=kT;k,sa fp=k esa nh xbZ gS
-
the surfaces of the lenses are as given in the

diagrams-

(1) R1 R2 (2) R ∞
(1) R1 R2 (2) R ∞
R ≠ R
1 2
R ≠ R
1 2

(3) R R (4) R ∞
(3) R R (4) R ∞

Q .36 A given ray of light suffers minimum deviation in Q.36 ,d nh xbZ izdk'k fdj.k ,d leckgq fizTe P esa U;wure
an equilateral prism P. Additional prisms Q and R fopyu n'kkZrh gSA ,d leku vkd`fr rFkk leku inkFkZ
of identical shape and of the same material as Pare
ds nks vfrfjDr fizTeksa rFkk dks ds lkFk fp=kkuqlkj
Q R P
now added as shown in figure. The ray will now
tksM+k tkrk gSaA izdk'k fdj.k vc n'kkZ;sxh
suffer- -

Q Q
P R P R

(1) greater deviation (1) vf/kd fopyu
(2) no deviation (2) dksbZ fopyu ugha
(3) same deviation as before (3) iwoZ ds leku fopyu

(4) total internal reflection (4) iw.kZ vkUrfjd ijkorZu

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Q .37 Sodium and copper have work functions 2.3 eV and Q .37 lkfsM;e rFkk dkiW j d s dk;ZQyu Øe'k% 2.3 eV rFkk

4.5 eV respectively. Then the ratio of the
gSA rc mudh rjxa n/S; Z dk vuiq kr gS] yxHkx
4.5 eV -
wavelengths is nearest to-

(1) 1 : 2 (2) 4 : 1 (1) 1 : 2 (2) 4 : 1

(3) 2 : 1 (4) 1 : 4 (3) 2 : 1 (4) 1 : 4

Q .38 A radiation of energy E falls normally on a Q.38 E ÅtkZ dh fofdj.k ,d iw.kZ ijkorZd lrg ij

perfectly reflecting surface. The momentum vfHkyEcor~ fxjrh gSA lrg dks LFkkukUrfjr laosx gS
-

transferred to the surface is-
(1) Ec (2) 2E/c
(1) Ec (2) 2E/c
(3) E/c (4) E/c2
(3) E/c (4) E/c2

Q .39 If a star converts all of its Helium into oxygen Q.39 ;fn ,d rkjk bldh lEiw.kZ ghfy;e dks vkWDlhtu

nucleus, find the amount of energy released per ukfHkd esa cny ns] rks izfr vkWDlhtu ukfHkd eqDr

nucleus of oxygen. He = 4.0026 amu, O = 15.9994 ÅtkZ dh ek=kk Kkr dhft,A
amu-
He = 4.0026 amu, O = 15.9994 amu

(1) 7.26 MeV (2) 7 MeV
(1) 7.26 MeV (2) 7 MeV
(3) 10.24 MeV (4) 5.12 MeV (3) 10.24 MeV (4) 5.12 MeV

Q .40 If radius of the 27Al nucleus is estimated to be 3.6 Q.40 ;fn 27Al ukfHkd dh f=kT;k 3.6 QehZ vkadh tk;s] rc
13 13

fermi, then the radius of 125Te nucleus be nearly- 125ukfHkd dh f=kT;k yxHkx gS -
52 52

QehZ QehZ
(1) 5 fermi (2) 4 fermi (1) 5 (2) 4

(3) 8 fermi (4) 6 fermi (3) 8 QehZ (4) 6 QehZ

tesZfu;e rFkk flfydu esa cU/k vUrjky esa Øe'k%
Q.41 The band gap in Germanium and Silicon in eV Q.41 eV

respectively is- gS -
(1) 0.7, 1.1 (2) 1.1, 0.7 (1) 0.7, 1.1 (2) 1.1, 0.7

(3) 1.1, 0 (4) 0, 1.1 (3) 1.1, 0 (4) 0, 1.1

laizs"k.k ,aVhuk dh Å¡pkbZ D;k gksuh pkfg, ;fn
Q .42 What should be height of transmitting antenna if the Q.42 T.V.
izlkj.k dh f=kT;k ds {ks=k esa fd;k tkuk gks
T.V. telecast is to cover a radius of 128 km ? 128 km ?
(1) 4000 (2) 6000 (1) 4000 (2) 6000
vuUr
(3) 2000 (4)
(3) 2000 (4) Infinite

fp=k esa ,d rdZ ifjiFk n'kkZ;k x;k gS
Q.43 -
Q .43 The diagram shows a logic network-
NAND
NAND
AND AND

NOT
NOT

NOT NAND NOT NAND
Which single gate is equivalent to the network ? dkSulk ,dy }kj ifjiFk ds rqY; g?S

(1) AND (2) NAND (1) AND (2) NAND

(3) NOR (4) EX-OR (3) NOR (4) EX-OR

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