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About Statistic Engineering Topic 1
(a) P(A ∪ B ∪ C) = P(A) + P(B) + P(C) = 0.2 + 0.3 + 0.4 = 0.9 (b) P(A ∩ B ∩ C) = 0 since the events are mutually exclusive (c) P(A ∩ B) = 0 since the events are mutually exclusive (d) P((A ∪ B) ∩ C) = P(C) = 0.4 since (A ∪ B) and C are mutually exclusive (e) P(A' ∩ B' ∩ C') = 1 - P(A ∪ B
Detailed Information
Author: | ['haris'] |
---|---|
Publication Year: | 2016 |
Pages: | 9 |
Language: | English |
Format: | |
Price: | FREE |
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