Principles of Foundation Engineering. Solution Manual

160 Pages·2007·2.41 MB·English

by  Braja M. Das

INSTRUCTOR'S SOLUTIONS MANUAL

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Instructor’s Solution Manual

‘To Accompany

Principles of Foundation Engineering, 6e

by

Braja M.Das

Convent

Page

Chapter

ul

ty

3

39

3

o

an

9

107

129

43

12

13

CuapTer 1

28D 6 rAT RNS?

+= Tonayoos,
peta TZ gop avi
Tew 14015

Ba (112) = Ste

t493= BEOSD,

a6
Tq Qo wees ee
(0.1 32.68),
om Fig 2129900) 5
PomFive 13 § [21828oan- ane

From Eqs (1.11) and (1.12) itcan be seen that

y 2m
Tew T4022

21648 KN fe?

we

Y= 1648 KN I rt» Gt

€.ean
Ite

e _ 081

PaO maT Tai

gs. (17) and (1.14): 8 a

[canzesy
1

1s

16

_268)981)0 +021) _

© Bg (dk p=. Teast = 1.58 KN fim?
6 tq ims y= 822 sowie?

SD 90) = 69.1%

4. om Eqs. (111) and (1.12): 7

feet, G2AN258 +057)
ite 14037

1292 b/f

a Ba. 15) Py

bh. Water to be added= 7, - y= 129.2- 122 7.20b/ i

tre 14057

nage

From Eqs. (111) and (I-12): yy = = e
‘wom Eqs (1 11) and (1.12): 7, Teogg 7 108 ben
a ID: y= Bas 1p OAKES, sy

Bg (1.19): 0, 0.82
1?

18

Refer to Table 15 for clasiication.

SOH 4:

SOIL B:

SOIC

SOM, O:

SON. ts

SOIL F:

SOIL A:

SOL B:

SOU. ¢:

SOI Dy

A-7449) (Note* PLis restr thea LL.— 30)
GI = (Py ~ 399102 + 0.005(LL — 40) + GOI Fi ~15)(R1- 10)

(65 ~ 350.2 +0.005(42 —40)] + 0.01665 - 15}06~10)=93=9
A68)

GL= (55 -35)[02 + 0.00508.-40}] + 001(SS—15Y13 -10)=54 = 5
130)

AA)

OT # (64 — 35)0.2 + 0 005(35 - 40)} + 0.01/64 ~ 1549 — 10) = 4.585.

Ans)

I= (yp 1521 ~ 10) = 0.01(33 ~ 159123 — 10) = 0.54 = 1

APHID) PL is greater that LI. 30)
G1=(16 — 35910 2+ 0 U05(52 — 40)] + 0.01(76 — 15)(24 - 10) = 19.2 = 19

‘Table 1 6: 65% passing No. 200 sieve Fine grained soi.j LL #42; P= 16
Figue 1.5: ML

Figwe 1.7: Phus No 200 > 30%; Phis No. 4 = 0

% sand > % giavel — sandy silt

‘Table 1.6: 55% passing No 200 sieve Fine grained soll. LL =38, PI=13
Figure 1.5: Plots below A-line — MIL.

Figure 1.7: Plus No. 200> 20%

% sand > % ravel - sandy sft

“Table 1.6: 8% passing Ne 200 sieve,
‘% sand > % geavel ~ sandy soil “SP
Figure 1.6: % gravel © 100-95 = 5% < 15% ~ poorly graded sand

‘Table 1 6: 65% passing No. 200 sieve. Fine grained soil LL=35,®1=9
Fige 15 -ML

Bhus No 200 ~ 36%4> 30%

°% sand (31%) > % gravel (5%) —sandy silt

*
SOI F: Table 1.6: 33% passing No 200 steve. 100% parsing No. siove. Sandy soi

LL=38,PI=13
Figme 1.5: Plots below A-line — SM
Figure 1.6; % gravel (096) < 15% silty sand

SOIL F Table 1.6: 76% passing No 200 sieve, LL 52, PL = 24
Figure 15: CH
Figme 1 7; Plus No. 200 is 100 ~ 76-24%
% sand > % gravel — fat clay with sand

19 Gite, a3

<a 063?
022 _ 740
03"
re, 14033

110 From &q (1.26)

_(@E YER ane é
onis=( 8 |e aa <2 Z

3126