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ArithmeticandGeometricSeries HSC Revision Day Arithmetic and Geometric Series WoononaHighSchool 2017 Teacher: Paul Hancock School: Woonona High School E-mail: [email protected] PaulHancock (WoononaHighSchool) Series T12017 1/23 Year Marks 2012 14 2013 12 2014 11 2015 8 2016 11 The average number of marks per exam is 11.2. ArithmeticandGeometricSeries Review HSC Question Analysis Let’s have a quick look at the number of marks allocated to the topic for HSC exams in the current format. PaulHancock (WoononaHighSchool) Series T12017 2/23 The average number of marks per exam is 11.2. ArithmeticandGeometricSeries Review HSC Question Analysis Let’s have a quick look at the number of marks allocated to the topic for HSC exams in the current format. Year Marks 2012 14 2013 12 2014 11 2015 8 2016 11 PaulHancock (WoononaHighSchool) Series T12017 2/23 ArithmeticandGeometricSeries Review HSC Question Analysis Let’s have a quick look at the number of marks allocated to the topic for HSC exams in the current format. Year Marks 2012 14 2013 12 2014 11 2015 8 2016 11 The average number of marks per exam is 11.2. PaulHancock (WoononaHighSchool) Series T12017 2/23 Well, the first term is a=3 and d =7−3=11−7=4. So the nth term is given by T =3+(n−1)×4 =4n−1. n Hence the 15th term is T =4(15)−1=59 15 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23 and d =7−3=11−7=4. So the nth term is given by T =3+(n−1)×4 =4n−1. n Hence the 15th term is T =4(15)−1=59 15 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Well, the first term is a=3 Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23 So the nth term is given by T =3+(n−1)×4 =4n−1. n Hence the 15th term is T =4(15)−1=59 15 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Well, the first term is a=3 and d =7−3=11−7=4. Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23 =4n−1. Hence the 15th term is T =4(15)−1=59 15 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Well, the first term is a=3 and d =7−3=11−7=4. So the nth term is given by T =3+(n−1)×4 n Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23 Hence the 15th term is T =4(15)−1=59 15 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Well, the first term is a=3 and d =7−3=11−7=4. So the nth term is given by T =3+(n−1)×4 =4n−1. n Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23 (A) ArithmeticandGeometricSeries MultipleChoice 2015 - Question 3 Example 1 (Q3) Well, the first term is a=3 and d =7−3=11−7=4. So the nth term is given by T =3+(n−1)×4 =4n−1. n Hence the 15th term is T =4(15)−1=59 15 Answer: PaulHancock (WoononaHighSchool) Series T12017 3/23

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Arithmetic and Geometric Series. Standard Questions. 2012 - Question 12c. (ii) How many tiles would Jay use altogether to make the first 20 rows?

Arithmetic and Geometric Series PDF

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Arithmetic and Geometric Series. Standard Questions. 2012 - Question 12c. (ii) How many tiles would Jay use altogether to make the first 20 rows?

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Author:	Unknown
Publication Year:	2017
Pages:	132
Language:	English
File Size:	0.75
Format:	PDF
Price:	FREE

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