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About AAU Strength of Materials Lecture Notes 09-05-21
Here are the steps to solve this example: a) Applying equilibrium of forces: ΣV = 0 => F1 = F2 = F3 = 100 kN b) For member S2 with cross section A = 24mm x 24mm: Design load Fd = F x γ = 100 kN x 1.5 = 150 kN Design normal stress σd = Fd/A = 150 kN / (24mm)2 = 31.25 kN/cm2 < Allowable stress of 22 kN/cm2. Design is safe. c) For member S3 with circular cross section: Design load Fd = F x γ = 100 kN
Detailed Information
| Author: | ['Tahir Aed'] |
|---|---|
| Publication Year: | 2012 |
| Pages: | 66 |
| Language: | English |
| Format: | |
| Price: | FREE |
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